Tiger Algebra/core — Chinese (Simplified) @ Weblate: The coordinates of Point 1 are:<br> <math>X_1= </math>{Step1Point1X}<br> and <math>Y

Translation

Key DistanceStep1TextUnit1

English

Fuzzy

Chinese (Simplified)

Needs editing

Skip

Key	English	Chinese (Simplified)
QEVFSStep5TextUnit3	The prime factorization of {Step5PrimeFactor} is {Step5PrimeFactorResult}. There are no square factors, so {Step5SquareRoot} cannot be simplified.	{Step5PrimeFactor}的质因数分解是{Step5PrimeFactorResult}。没有平方因数，所以不能简化{Step5SquareRoot}。
QEVFSStep6Title1	Solve the equation for {Step6VariableCharacter}	求解{Step6VariableCharacter}的方程
QEVFSStep6TextUnit1	{Step6EquationToSolve}	{Step6EquationToSolve}
QEVFSStep6TextUnit2	The ± means two answers are possible.	±表示有两个可能的答案。
QEVFSStep6TextUnit2b	The ± means two answers are possible, but since zero is result of the square root, we have one solution:	±表示有两个可能的答案，但由于平方根的结果是零，我们只有一个解:
QEVFSStep6TextUnit3	{Step6Solution1}	{Step6Solution1}
QEVFSStep6TextUnit4	or:	或者:
QEVFSStep6TextUnit5	{Step6Solution2}	{Step6Solution2}
QEVFSStep6TextUnit6	Separate the equations:<br> {Step6EquationPlus} and {Step6EquationMinus}	分离方程:<br> {Step6EquationPlus}和{Step6EquationMinus}
OOOSolverFinalResultSpokenDescription	The final result is {SolutionFinalResult}	最终的结果是{SolutionFinalResult}
OOOSolverFinalResultSpokenDescriptionAtEnding	And so the final result is {SolutionFinalResult}	因此，最终的结果是{SolutionFinalResult}
OOOSolverSolverSpokenDescription	This deals with the order of operations	这涉及到运算顺序
OOOSolverSolverSpokenDescriptionIntro	You asked Tiger to calculate	你要求Tiger进行计算
OOOStep1Title	Simplify the expression	简化表达式
DistanceStep1Title	Plot the two points and calculate the distance using the formula	使用距离公式求距离
DistanceStep1TextUnit1	The coordinates of Point 1 are:<br> <math>X_1= </math>{Step1Point1X}<br> and <math>Y_1= </math>{Step1Point1Y}<br>	点1的坐标是:<br> <math>X= </math>{Step1Point1X}<br> <math>Y= </math>{Step1Point1Y}<br> {Step1Point1}
DistanceStep1TextUnit2	The coordinates of Point 2 are:<br> <math>X_2= </math>{Step1Point2X}<br> and <math>Y_2= </math>{Step1Point2Y}<br>	点2的坐标是:<br> <math>X= </math>{Step1Point2X}<br> <math>Y= </math>{Step1Point2Y}<br> {Step1Point2}
DistanceStep1TextUnit3	<b>d</b> is the distance between the two points.	<b>d</b>是两点之间的距离。
DistanceBetweenTwoPointsSolverTransitionSubstitute	Plug the coordinates of the points into the formula	将点的坐标代入距离公式:
DistanceBetweenTwoPointsCalculator	Distance between two points	两点之间的距离
DistanceBetweenTwoPointsCalculator.plugin	finding the distance between two points on an XY plane	在XY平面上找两点之间的距离
distanceResultType	The distance between the 2 points is:	2点之间的距离是:
DistanceNTX2	{Step1Point1X2Equals}	{Step1Point1X2Equals}
DistanceNTY1	{Step1Point1Y1Equals}	{Step1Point1Y1Equals}
DistanceNTY2	{Step1Point1Y2Equals}	{Step1Point1Y2Equals}
DistanceSolveRadical	Solve the problem under the radical.	解决根号下的问题。
DistanceSolveSQRT	Find the square root under the radical.	找到根号下的平方根。
DistanceSolution	And so, the solution is {Step1Solution}	因此，解决方案是{Step1Solution}
DistanceP1	P1	P1
DistanceP2	P2	P2
DistanceLine	d	d

Key	English	Chinese (Simplified)
DistanceBetweenTwoPointsSolverNTPythagoreanTheoremNT2	This gives us the distance formula.	这就得出了距离公式。
DistanceBetweenTwoPointsSolverTransitionSubstitute	Plug the coordinates of the points into the formula	将点的坐标代入距离公式:
DistanceBetweenTwoPointsSpokenDescription	This deals with the distance between two points.	这涉及到两点之间的距离。
DistanceBetweenTwoPointsSpokenDescriptionIntro	You asked Tiger to calculate
DistanceLine	d	d
DistanceNTX1	{Step1Point1X1Equals}	{Step1Point1X1Equals}
DistanceNTX2	{Step1Point1X2Equals}	{Step1Point1X2Equals}
DistanceNTY1	{Step1Point1Y1Equals}	{Step1Point1Y1Equals}
DistanceNTY2	{Step1Point1Y2Equals}	{Step1Point1Y2Equals}
DistanceP1	P1	P1
DistanceP2	P2	P2
distanceResultType	The distance between the 2 points is:	2点之间的距离是:
DistanceSolution	And so, the solution is {Step1Solution}	因此，解决方案是{Step1Solution}
DistanceSolveRadical	Solve the problem under the radical.	解决根号下的问题。
DistanceSolveSQRT	Find the square root under the radical.	找到根号下的平方根。
DistanceStep1TextUnit1	The coordinates of Point 1 are:<br> <math>X_1= </math>{Step1Point1X}<br> and <math>Y_1= </math>{Step1Point1Y}<br>	点1的坐标是:<br> <math>X= </math>{Step1Point1X}<br> <math>Y= </math>{Step1Point1Y}<br> {Step1Point1}
DistanceStep1TextUnit2	The coordinates of Point 2 are:<br> <math>X_2= </math>{Step1Point2X}<br> and <math>Y_2= </math>{Step1Point2Y}<br>	点2的坐标是:<br> <math>X= </math>{Step1Point2X}<br> <math>Y= </math>{Step1Point2Y}<br> {Step1Point2}
DistanceStep1TextUnit3	<b>d</b> is the distance between the two points.	<b>d</b>是两点之间的距离。
DistanceStep1Title	Plot the two points and calculate the distance using the formula	使用距离公式求距离
DividingExponents	Dividing exponents	分割指数
DividingExponentsContent	<div style="white-space: normal;"> <p>When dividing expressions with exponents, you can use the properties of exponents to simplify the expression. Here's how:</p> <h2>Step 1: Subtract Exponents</h2> <p>To divide two terms with the same base, subtract the exponent of the divisor from the exponent of the dividend. For example, <math>x^a ÷ x^b = x^(a - b)</math>.</p> <p>For instance, if you have <math>x^5 ÷ x^2</math>, you subtract the exponents: <math>x^(5 - 2) = x^3</math>.</p> <h2>Step 2: Simplify</h2> <p>If there are additional terms in the expression, simplify them as well. For example, if you have <math>(x^5 * y^3) ÷ (x^2 * y)</math>, divide the x's and y's separately: <math>x^(5 - 2) * y^(3 - 1) = x^3 * y^2</math>.</p> <p>Remember, when dividing exponents with the same base, subtract the exponents.</p> <p>This process is crucial in algebra and higher-level mathematics when dealing with expressions containing exponents.</p> </div>	Tiger 代数求解器会向您逐步展示如何处以指数。例如：
DividingFractions	Dividing fractions	分数的除法
DividingFractionsContent	<div style="white-space: normal;"> <p>Dividing fractions is a fundamental operation in mathematics, especially in arithmetic and algebra. When dividing fractions, we follow specific rules to simplify the process and obtain the result.</p> <h2>Basic Concepts</h2> <p>To divide fractions, it's important to understand the following concepts:</p> <ul> <li><strong>Fractions:</strong> Numbers that represent parts of a whole or ratios of two quantities.</li> <li><strong>Dividing fractions:</strong> The process of dividing one fraction by another to find the quotient.</li> <li><strong>Reciprocal:</strong> The reciprocal of a fraction <math>\frac{a}{b}</math> is <math>\frac{b}{a}</math>.</li> </ul> <h2>Division Techniques</h2> <p>There are two common techniques to divide fractions:</p> <ul> <li><strong>Using reciprocals:</strong> Multiply the first fraction by the reciprocal of the second fraction.</li> <li><strong>Converting to multiplication:</strong> Convert the division operation to multiplication by multiplying the first fraction by the reciprocal of the second fraction.</li> </ul> <h2>Examples</h2> <p>Let's consider a few examples to illustrate the division of fractions:</p> <h3>Example 1:</h3> <p>Divide <math>\frac{3}{4}</math> by <math>\frac{1}{2}</math></p> <p>Using the reciprocal technique, we multiply the first fraction by the reciprocal of the second fraction:</p> <p><math>\frac{3}{4} \div \frac{1}{2} = \frac{3}{4} \times 2 = \frac{6}{4}</math></p> <p>Since <math>\frac{6}{4}</math> can be simplified to <math>\frac{3}{2}</math>, the result is <math>\frac{3}{2}</math>.</p> <h3>Example 2:</h3> <p>Divide <math>\frac{5}{8}</math> by <math>\frac{2}{3}</math></p> <p>We convert the division operation to multiplication by multiplying the first fraction by the reciprocal of the second fraction:</p> <p><math>\frac{5}{8} \div \frac{2}{3} = \frac{5}{8} \times \frac{3}{2}</math></p> <p>After simplification, we get the result as <math>\frac{15}{16}</math>.</p> <h2>Conclusion</h2> <p>Dividing fractions is a fundamental operation that plays a crucial role in various mathematical contexts. Mastering the techniques of fraction division enables efficient problem-solving and enhances mathematical understanding.</p> </div>	Tiger 代数计算器分割分数，向您展示逐步的解决方案，例如：
Domain	Domain	定义域
DomainRangeAndRelationFromOrderedPairsTopicContent	In order to find the domain and range of ordered pairs and determine whether they are functions, we need to first understand a few key concepts.<br><br> <b>Ordered pair</b><br> An ordered pair is represented by two numbers that are written in a specific order, usually in parentheses, with a comma between them. For example: <math>(4, -5)</math> is an ordered pair. On an xy-plane—also called a Cartesian plane—an ordered pair represents the location of a point, where the first number in parentheses is the x-coordinate of the point and the second number is the y-coordinate of the point: <math>(x,y)</math>. In this case: <math>x=4, y=-5</math><br> To map these coordinates on a plane, we move outwards from the plane's origin <math>(0,0)</math> to the right or left on the x-axis, or up or down on the y-axis.<br><br> <img src="/images/domain-range-img1.png" alt="Domain range and relation from ordered pairs"> <br> <b>Relation</b> A relation describes how ordered pairs are related and, more specifically, whether or not they are functions. A relation between ordered pairs is a function if it has only one y-value (output) for each x-value (input). If an x-value has more than one y-value, then the relation is not a function.<br> <img src="/images/domain-range-img2.png" alt="Domain range and relation from ordered pairs"> <br> <b>Function</b> A function is a relation that takes a chosen input and creates an output. For example, the function <math>f(x)=2x</math> multiplies every input <math>(x)</math> by <math>2</math> to create an output. A relation between ordered pairs is a function if it has only one y-value (output) for each x-value (input). If an x-value has more than one y-value, then the relation is not a function. <br><br> <b>Domain</b> The domain represents all the possible inputs for a variable of a function. It is considered an independent variable because it represents the quantity being manipulated and is not dependent on any other factor. Its value is represented by the first number in an ordered pair. For example, in the input <math>(4, -5)</math> , <math>4</math> is the domain. <br><br> <b>Range</b> The range represents all the possible outputs of a function. It is considered a dependant variable because it is dependent on how the independent variable is manipulated. Its value is represented by the second number in an ordered pair. In the ordered pair <math>(4, -5)</math> , <math>-5</math> is the range. <br> <img src="/images/domain-range-img3.png" alt="Domain range and relation from ordered pairs">	要找出有序对的域和范围，并确定它们是否为函数，我们首先需要理解一些关键概念。<br><br> <b>有序对</b><br> 一个有序对由两个以特定顺序写下的数字表示，通常包含在括号内，两者之间用逗号分隔。例如：<math>(4, -5)</math> 是一个有序对。在xy平面——也称为笛卡尔平面——上，一个有序对表示一个点的位置，其中括号内的第一个数字是点的x坐标，第二个数字是点的y坐标：<math>(x,y)</math>。在此情况下：<math>x=4, y=-5</math><br> 要在平面上绘制这些坐标，我们从平面的原点 <math>(0,0)</math> 向x轴的左右或y轴的上下移动。<br><br> <img src="/images/domain-range-img1.png" alt="有序对的域范围和关系"> <br> <b>关系</b> 关系描述了有序对如何相关，更具体地说，它们是否是函数。如果有序对关系每个x值（输入）只有一个y值（输出），那么这个关系是一个函数。如果一个x值有多个y值，那么这个关系就不是函数。<br> <img src="/images/domain-range-img2.png" alt="有序对的域范围和关系"> <br> <b>函数</b> 函数是一种关系，它接受一个选定的输入并生成输出。例如，函数 <math>f(x)=2x</math> 将每个输入 <math>(x)</math> 乘以 <math>2</math> 以生成输出。如果有序对关系每个x值（输入）只有一个y值（输出），那么这个关系是一个函数。如果一个x值有多个y值，那么这个关系就不是函数。 <br><br> <b>域</b> The domain代表函数的一个变量的所有可能输入。它被认为是一个独立变量，因为它代表被操纵的数量，不依赖于任何其他因素。它的值由有序对中的第一个数字表示。例如，在输入 <math>(4, -5)</math> 中， <math>4</math> 是域。 <br><br> <b>范围</b> The range代表函数的所有可能输出。它被认为是一个依赖变量，因为它取决于如何操纵独立变量。它的值由有序对中的第二个数字表示。在有序对 <math>(4, -5)</math> 中， <math>-5</math> 是范围。<br> <img src="/images/domain-range-img3.png" alt="有序对的域范围和关系">
DomainRangeAndRelationFromOrderedPairsTopicTitle	Domain range and relation from ordered pairs	有序对的域范围和关系
DomainRangeRelationFromOrderedPairs	Finding the domain and range of a relation from ordered pairs	从有序对中找出关系的定义域和值域
DomainRangeRelationFromOrderedPairs3TableTitle	A relation is considered a function when every x-input has only one y-output.	当每个x输入只有一个y输出时，关系被视为函数。
DomainRangeRelationFromOrderedPairsFinalResultIsFunction	The list of ordered pairs is a function.	有序对列表是一个函数。
DomainRangeRelationFromOrderedPairsFinalResultIsNotFunction	The list of ordered pairs is not a function.	有序对列表不是一个函数。