Tiger Algebra/core — Chinese (Simplified) @ Weblate: Plug the coordinates of the points into the formula

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Key DistanceBetweenTwoPointsSolverTransitionSubstitute

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Key	English	Chinese (Simplified)
QEVFSStep6TextUnit2	The ± means two answers are possible.	±表示有两个可能的答案。
QEVFSStep6TextUnit2b	The ± means two answers are possible, but since zero is result of the square root, we have one solution:	±表示有两个可能的答案，但由于平方根的结果是零，我们只有一个解:
QEVFSStep6TextUnit3	{Step6Solution1}	{Step6Solution1}
QEVFSStep6TextUnit4	or:	或者:
QEVFSStep6TextUnit5	{Step6Solution2}	{Step6Solution2}
QEVFSStep6TextUnit6	Separate the equations:<br> {Step6EquationPlus} and {Step6EquationMinus}	分离方程:<br> {Step6EquationPlus}和{Step6EquationMinus}
OOOSolverFinalResultSpokenDescription	The final result is {SolutionFinalResult}	最终的结果是{SolutionFinalResult}
OOOSolverFinalResultSpokenDescriptionAtEnding	And so the final result is {SolutionFinalResult}	因此，最终的结果是{SolutionFinalResult}
OOOSolverSolverSpokenDescription	This deals with the order of operations	这涉及到运算顺序
OOOSolverSolverSpokenDescriptionIntro	You asked Tiger to calculate	你要求Tiger进行计算
OOOStep1Title	Simplify the expression	简化表达式
DistanceStep1Title	Plot the two points and calculate the distance using the formula	使用距离公式求距离
DistanceStep1TextUnit1	The coordinates of Point 1 are:<br> <math>X_1= </math>{Step1Point1X}<br> and <math>Y_1= </math>{Step1Point1Y}<br>	点1的坐标是:<br> <math>X= </math>{Step1Point1X}<br> <math>Y= </math>{Step1Point1Y}<br> {Step1Point1}
DistanceStep1TextUnit2	The coordinates of Point 2 are:<br> <math>X_2= </math>{Step1Point2X}<br> and <math>Y_2= </math>{Step1Point2Y}<br>	点2的坐标是:<br> <math>X= </math>{Step1Point2X}<br> <math>Y= </math>{Step1Point2Y}<br> {Step1Point2}
DistanceStep1TextUnit3	<b>d</b> is the distance between the two points.	<b>d</b>是两点之间的距离。
DistanceBetweenTwoPointsSolverTransitionSubstitute	Plug the coordinates of the points into the formula	将点的坐标代入距离公式:
DistanceBetweenTwoPointsCalculator	Distance between two points	两点之间的距离
DistanceBetweenTwoPointsCalculator.plugin	finding the distance between two points on an XY plane	在XY平面上找两点之间的距离
distanceResultType	The distance between the 2 points is:	2点之间的距离是:
DistanceNTX2	{Step1Point1X2Equals}	{Step1Point1X2Equals}
DistanceNTY1	{Step1Point1Y1Equals}	{Step1Point1Y1Equals}
DistanceNTY2	{Step1Point1Y2Equals}	{Step1Point1Y2Equals}
DistanceSolveRadical	Solve the problem under the radical.	解决根号下的问题。
DistanceSolveSQRT	Find the square root under the radical.	找到根号下的平方根。
DistanceSolution	And so, the solution is {Step1Solution}	因此，解决方案是{Step1Solution}
DistanceP1	P1	P1
DistanceP2	P2	P2
DistanceLine	d	d
MidpointStep1Title	Plot the two points and calculate the midpoint using the formula	使用中点公式求中点
MidpointStep1TextUnit1	The coordinates of Point 1 are: <br> {Step1Point1} <br>	点1 (P1) 的坐标是: <br> {Step1Point1} <br>
MidpointStep1TextUnit2	<br>The coordinates of Point 2 are: <br> {Step1Point2} <br>	<br>点2 (P2) 的坐标是: <br> {Step1Point2} <br>

Key	English	Chinese (Simplified)
DecimalToFractionStep3TextUnit1	The decimal <math>{decimalInput}</math> in lowest terms is <math>{fractionResult}</math>.	<math>{decimalInput}={fractionResult}</math>.
DecimalToFractionStep3Title1	Final reduced fraction	写出化简后的分数
DeMoivreFormula	De Moivre formula	德穆瓦公式
DeMoivreFormulaContent	De Moivre’s formula, also called de Moivre’s theorem or de Moivre’s identity, is used to determine the nth power of a complex number. It states that if n is any integer and x is a real number, then <math>(cos(x) + i sin(x))^n = cos(nx) + i sin(nx)</math>, where i is the imaginary unit <math>(i^2 = −1)</math>. The expression <math>cos(x) + i sin(x)</math> is sometimes reduced to <math>cis(x)</math>. De Moivre’s formula is a direct method for solving problems involving powers of complex numbers. In an extended form, it can be used to find the nth roots of a complex number.	德穆瓦公式，也被称为德穆瓦定理或德穆瓦身份，用于确定复数的第n次方。它表明，如果n是任何整数且x是一个实数，那么<math>(cos(x) + isin(x))^n = cos(nx) + isin(nx)</math>，其中i是虚单位<math>(i^2 = -1)</math>。表达式<math>cos(x) + i sin(x)</math>有时被简写为<math>cis(x)</math>。德穆瓦公式是解决涉及复数幂的问题的一种直接方法。在扩展形式中，它可以用来找到一个复数的第n个根。
DistanceBetweenTwoPointsAndTheirMidpoint	Distance between two points	两点之间的距离
DistanceBetweenTwoPointsAndTheirMidpointContent	The distance formula, an application of the Pythagorean theorem, is a very helpful tool for finding the distance between two points. The Pythagorean theorem states the following: in a right triangle, the length of side <math>a</math> squared plus the length of side <math>b</math> squared is equal to the length of the hypotenuse (side <math>c</math>) squared.<br> <math>a^2+b^2=c^2</math><br> <img src="/images/distance-between-two-points-graph1.png" alt="Distance between two points graph"><br><br> The hypotenuse (<math>c</math>) is the longest side of a right triangle and is always opposite the right angle. The length of the hypotenuse also represents the distance between points <b>A</b> and <b>B</b>, which can each be represented by two coordinates: an <math>x</math> coordinate and a <math>y</math> coordinate.<br> Point <b>A</b> = <math>(x_1,y_1)</math><br> Point <b>B</b> = <math>(x_2,y_2)</math><br><br> To get the distance formula, we can rewrite the Pythagorean theorem as:<br> <math>d=\sqrt{(x_2−x_1)^2+(y_2−y_1)^2}</math><br> in which <math>d</math> represents the distance between points <b>A</b> and <b>B</b>, and the Xs and Ys represent the <math>x</math> and <math>y</math> coordinates of points <b>A</b> and <b>B</b>.<br><br> In order to find the distance between two points, enter their coordinates (for example (1,2) and (3,4)) and click the solve button.	距离公式是毕达哥拉斯定理的一种应用，这是一个求解两点间距离的非常实用的工具。毕达哥拉斯定理陈述如下：在直角三角形中，边<math>a</math>的平方加上边<math>b</math>的平方等于斜边（边<math>c</math>）的平方。<br> <math>a^2+b^2=c^2</math>。<br> <img src="/images/distance-between-two-points-graph1.png" alt="两点之间的距离曲线图"><br><br> 斜边（<math>c</math>）是直角三角形的最长边，总是对直角来说最长的那条边。斜边的长度也代表了点<b>A</b>和点<b>B</b>之间的距离，这两个点可以分别用两个坐标（一个<math>x</math>坐标和一个<math>y</math>坐标）来表示。。<br> 点 <b>A</b> = <math>(x_1,y_1)</math><br> 点 <b>B</b> = <math>(x_2,y_2)</math><br><br> 为了获得距离公式，我们可以将毕达哥拉斯定理重写为：<br> <math>d=\sqrt{(x_2−x_1)^2+(y_2−y_1)^2}</math><br> 在这个公式中，<math>d</math>代表点<b>A</b>和点<b>B</b>之间的距离，X和Y代表点<b>A</b>和<b>B</b>的<math>x</math>和<math>y</math>坐标。<br><br> 为了找出两点之间的距离，输入它们的坐标（例如(1,2)和(3,4)）并点击求解键。
DistanceBetweenTwoPointsCalculator	Distance between two points	两点之间的距离
DistanceBetweenTwoPointsCalculator.plugin	finding the distance between two points on an XY plane	在XY平面上找两点之间的距离
DistanceBetweenTwoPointsFinalResultSpokenDescription	The distance between the two points is {SolutionFinalResult}
DistanceBetweenTwoPointsFinalResultSpokenDescriptionAtEnding	And so the distance between the two points is {SolutionFinalResult}
DistanceBetweenTwoPointsMetaVideoDescription	See how to easily find the distance between two points p1 {0} and p2 {1} with our clear, step-by-step video guide on Tiger Algebra. Also, check out https://www.tiger-algebra.com{2} for more tips and tricks	在老虎代数上，看看如何轻松找出两点p1 {0} 和p2 {1} 之间的距离，我们有详细的逐步视频指南。另外，访问 https://www.tiger-algebra.com{2} 获取更多技巧和窍门
DistanceBetweenTwoPointsMetaVideoTags	math, algebra, tiger-algebra, e-learning, distance, between two points	数学, 代数, 老虎代数, 电子学习, 距离, 两点之间
DistanceBetweenTwoPointsMetaVideoTitle	Find the distance between two points p1 {0} and p2 {1}: Step-by-Step Video Solution	找出两点p1 {0} 和p2 {1} 之间的距离：逐步视频解答
DistanceBetweenTwoPointsSolverNTPythagoreanTheoremNT	First, take the square root of both sides of the Pythagorean theorem.	首先，对勾股定理的两侧取平方根。
DistanceBetweenTwoPointsSolverNTPythagoreanTheoremNT2	This gives us the distance formula.	这就得出了距离公式。
DistanceBetweenTwoPointsSolverTransitionSubstitute	Plug the coordinates of the points into the formula	将点的坐标代入距离公式:
DistanceBetweenTwoPointsSpokenDescription	This deals with the distance between two points.	这涉及到两点之间的距离。
DistanceBetweenTwoPointsSpokenDescriptionIntro	You asked Tiger to calculate
DistanceLine	d	d
DistanceNTX1	{Step1Point1X1Equals}	{Step1Point1X1Equals}
DistanceNTX2	{Step1Point1X2Equals}	{Step1Point1X2Equals}
DistanceNTY1	{Step1Point1Y1Equals}	{Step1Point1Y1Equals}
DistanceNTY2	{Step1Point1Y2Equals}	{Step1Point1Y2Equals}
DistanceP1	P1	P1
DistanceP2	P2	P2
distanceResultType	The distance between the 2 points is:	2点之间的距离是:
DistanceSolution	And so, the solution is {Step1Solution}	因此，解决方案是{Step1Solution}
DistanceSolveRadical	Solve the problem under the radical.	解决根号下的问题。
DistanceSolveSQRT	Find the square root under the radical.	找到根号下的平方根。
DistanceStep1TextUnit1	The coordinates of Point 1 are:<br> <math>X_1= </math>{Step1Point1X}<br> and <math>Y_1= </math>{Step1Point1Y}<br>	点1的坐标是:<br> <math>X= </math>{Step1Point1X}<br> <math>Y= </math>{Step1Point1Y}<br> {Step1Point1}

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DistanceBetweenTwoPointsSolverTransitionSubstitute

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Fuzzy

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7 hours ago

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core/TigerAlgebra.Localization/Resources/TigerSharedResource.zh-Hans.resx, string 338